If a1 and a2 are in ratio 1-2 and Ka1-2- 10-4- then what will be the value of Ka2-

The correct option is B 8× 10^ 4 α_1/α_2=1/2=√(K_a1/K_a2) ⇒ K_a_2=4K_a_1=4× 2× 10^ 4=8× 10^ 4 ...

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Byju's Answer

Standard XII

Mathematics

Sum of n Terms

If a1 and ...

Question

If $a_{1}$ and $a_{2}$ are in ratio $1 : 2$ and $K_{a_{1}} = 2 \times 10^{- 4}$ , then what will be the value of $K_{a_{2}}$ ?

8 \times 10^{- 4}

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2 \times 10^{- 4}

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4 \times 10^{- 4}

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1 \times 10^{- 4}

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Solution

The correct option is B $8 \times 10^{- 4}$
$\frac{α_{1}}{α_{2}} = \frac{1}{2} = \sqrt{\frac{K_{a 1}}{K_{a 2}}}$

$\Rightarrow K_{a_{2}} = 4 K_{a_{1}} = 4 \times 2 \times 10^{- 4} = 8 \times 10^{- 4}$

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If a1 and a2 are in ratio 1:2 and Ka1=2×10−4, then what will be the value of Ka2?

The correct option is B 8×10−4α1α2=12=√Ka1Ka2⇒Ka2=4Ka1=4×2×10−4=8×10−4

If $a_{1}$ and $a_{2}$ are in ratio $1 : 2$ and $K_{a_{1}} = 2 \times 10^{- 4}$ , then what will be the value of $K_{a_{2}}$ ?

The correct option is B $8 \times 10^{- 4}$
$\frac{α_{1}}{α_{2}} = \frac{1}{2} = \sqrt{\frac{K_{a 1}}{K_{a 2}}}$

$\Rightarrow K_{a_{2}} = 4 K_{a_{1}} = 4 \times 2 \times 10^{- 4} = 8 \times 10^{- 4}$