If a = 1 and b = 0, find the value of −1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10].[3Marks]
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Solution
−1[a−3{b−4(a−¯¯¯¯¯¯¯¯¯¯¯¯b−8)+4a}+10]=−1[a−3{b−4(a−b+8)+4a}+10]=−1[a−3{b−4a+4b−32+4a}+10][1Mark]=−1[a−3{5b−32}+10]=−1[a−15b+96+10]=−1[a−15b+106]=−a+15b−106[1Mark]
If a = 1 and b = 0, −a+15b−106=−1+0−106=−107[1Mark]