You visited us 1 times! Enjoying our articles? Unlock Full Access!

Discriminant

If a = 1, b...

Question

If $a = 1, b = 8$ and $c = 15$ , then find the value of $b^{2} - 4 a c =$

Open in App

Solution

Given, $a = 1, b = 8$ and $c = 15$
then, $b^{2} - 4 a c = (8)^{2} - 4 \times 1 \times 15$
$= 64 - 60 = 4$

Suggest Corrections

Similar questions

b^{2} - 4 a c

a > 0

b^{2} - 4 a c < 0

\int \frac{d x}{a x^{2} + b x + c}

μ {tan}^{- 1} \frac{x + A}{B} + C

A, B, C, μ

a > 0

b^{2} - 4 a c < 0

a x^{2} + b x + C

\int \frac{1}{\sqrt{x^{2} + 2 x + 10}} d x = {sinh}^{- 1} \frac{x + 1}{3} + c

a > 0, b^{2} - 4 a c < 0

\int \frac{d x}{\sqrt{a x^{2} + b x + c}} = \frac{1}{\sqrt{a}} {sinh}^{- 1} (\frac{2 a x + b}{\sqrt{4 a c - b^{2}}}) + k

If b² – 4ac = 0 then The roots of the Quadratic equation ax² + bx + c = 0 are given by :

(α - β) = \frac{\sqrt{b^{2} - 4 a c}}{a}

α β = \frac{c}{a}

α^{3} - β^{3}

Join BYJU'S Learning Program