Question

If $a=-10$ , evaluate
(ii) $a^2+8a$ .

Answer 1

Given : $a^2+8a$

Substituting $a=-10$ in the given expression

$a^2+8a=(-10{)}^2+8(-10$)

$=100-80$

$=20$

Hence, the value of $a^2+8a$ for $a=-10$ is $20$.