Question

If $a=-10$, evaluate
(iii) $\frac{1}{5}\times (a{)}^2$

Answer 1

Given : $\frac{1}{5}\times (a{)}^2$

Substituting $a=-10$ in the given expression

$\frac{1}{5}\times (a{)}^2=\frac{1}{5}\times (-10{)}^2$

$=\frac{1}{5}\times 100$

$=20$

Hence, the value of $\frac{1}{5}\times (a{)}^2$ for $a=-10$ is $20$ .