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Byju's Answer
Standard VII
Mathematics
Multiplication of Integers
If A 10101200...
Question
If A
1
0
1
0
1
2
0
0
4
, then show that |3 A| = 27 |A|.
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Solution
A
=
1
0
1
0
1
2
0
0
4
⇒
3
A
=
3
0
3
0
3
6
0
0
12
Multiplying
each
element
of
A
by
3
⇒
3
A
=
-
1
1
+
1
3
36
-
0
+
-
1
1
+
2
0
0
-
0
+
-
1
1
+
3
3
0
-
0
=
3
36
-
0
-
0
0
-
0
+
3
0
-
0
Expanding
along
R
1
=
3
×
36
=
108
.
.
.
1
⇒
A
=
-
1
1
+
1
1
4
-
0
+
-
1
1
+
2
0
0
-
0
+
-
1
1
+
3
1
0
-
0
=
1
4
-
0
-
0
0
-
0
+
1
0
-
0
=
4
Expanding
along
R
1
⇒
27
A
=
27
×
4
=
108
.
.
.
2
∴
3
A
=
27
A
From
eqs
.
(
1
)
and
(
2
)
Suggest Corrections
0
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