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Question

If a + 10o, 3a + 10o, 5a - 10o and 3a - 10o are the angles of a quadrilateral, then what is the value of a?


A

50o

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B

40o

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C

20o

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D

30o

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Solution

The correct option is D

30o


Given, a + 10o, 3a + 10o, 5a - 10o and 3a - 10o are the angles of a quadrilateral.

We know that the sum of angles of a quadrilateral is 360o.

Therefore,

(a + 10o)+ (3a + 10o) + (5a - 10o) +(3a - 10o) = 360o

12a = 360o

a = 30o


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