If A > 11, B > 21, C > 30, D > 40 and E > 50, then how many positive integral solutions exist for A + B + C + D + E = 2012?
A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D A + B + C + D + E = 2012 (A>11, B>21, C>30, D>40, E>50) This is a lower limit Similar->Different question. So, we assign the minimum values that can be taken by each of A, B, C, D and E and reframe the equation: A + B + C + D + E = 1855 (Assigning 12 to A, 22 to B, 31 to C, 41 to D and 51 to E) Using the 1-0 method: