wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If A > 11, B > 21, C > 30, D > 40 and E > 50, then how many positive integral solutions exist for A + B + C + D + E = 2012?

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D


A + B + C + D + E = 2012 (A>11, B>21, C>30, D>40, E>50)
This is a lower limit Similar->Different question.
So, we assign the minimum values that can be taken by each of A, B, C, D and E and reframe the equation:
A + B + C + D + E = 1855 (Assigning 12 to A, 22 to B, 31 to C, 41 to D and 51 to E)
Using the 1-0 method:

Required Answer = 1859C4.Option (d)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A+B+C=N (N Fixed)
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program
CrossIcon