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Question

If a 1200 W electric iron is used daily for 30 minutes, calculate the electricity consumed for the month of june.

A
15 kWhr
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B
18 kWhr
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C
21 kWhr
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D
24 kWhr
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Solution

The correct option is B 18 kWhr
Given:
An electric iron of 1200 W=1.2 kW
Time =30 minutes=0.5 hours
Number of days in the month of june =30 days
Total electric consumption 1.2 ×0.5 ×30=18 kWhr

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