If a $1200 W$ electric iron is used daily for $30$ minutes, calculate the electricity consumed for the month of june.

15 k W h r

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18 k W h r

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21 k W h r

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24 k W h r

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Solution

The correct option is B $18 k W h r$
Given:
An electric iron of $1200 W = 1.2 k W$
Time $= 30 m i n u t e s = 0.5 h o u r s$
Number of days in the month of june $= 30$ days
Total electric consumption $1.2 \times 0.5 \times 30 = 18 k W h r$

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Question 20
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