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Question

If A=122212221, then prove that A2 − 4A − 5I = O.

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Solution

Given: A=122212221Now,A2=AAA2=122212221122212221A2=1+4+42+2+42+4+22+2+44+1+44+2+22+4+24+2+24+4+1A2=988898889A2-4A-5I A2-4A-5I=988898889-4122212221-5100010001 A2-4A-5I=988898889-488848884-500050005 A2-4A-5I=9-4-58-8-08-8-08-8-09-4-58-8-08-8-08-8-09-4-5 A2-4A-5I=000000000=0

Hence proved.

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