Question

If $A=(1,2,3)$ and $B(3,5,7)$ and $P,Q$ are the points on $AB$ such that $AP=PQ=QB,$ then the mid point of $PQ$ is

• A. $(2,3,5)$
• B. $(2,\frac{7}{2},5)$
• C. $(2,4,5)$
• D. $(4,7,0)$

Answer 1

The correct option is B $(2,\frac{7}{2},5)$

Given: $A=(1,2,3)$ and $B(3,5,7)$
Now, mid point of $PQ=$ mid point of $AB$.
$\therefore$ Mid point of $PQ$ is $(\frac{1+3}{2},\frac{2+5}{2},\frac{3+7}{2})$
Mid point of $PQ$ is $(2,\frac{7}{2},5)$