The correct options are
A (A∩B)∪(A∩C)
D {1,2}
Given A={1,2,3}, B={2,4,5} and C={4,1,9}.
Then, A∩(B∪C)={1,2,3}∩({2,4,5}∪{4,1,9})
={1,2,3} ∩{1,2,4,5,9}
={1,2}.
Also, (A∩B)∪(A∩C)=({1,2,3}∩{2,4,5})∪({1,2,3}∩{4,1,9})
={2}∪{1}
={1,2}.
This property of sets A, B and C such that
A∩(B∪C)=(A∩B)∪(A∩C) is called the distributive property of sets (intersection over union).