If $a = - 13, b = 5 a n d c = - 11$ Verify that $a + b = b + a$

Open in App

Solution

As we have $a + b = b + a$ also, $a = - 13, b = 5 a n d c = - 11$
$a + b = b + a$
$\Rightarrow - 13 + 5 = 5 + (- 13) \Rightarrow - 8 = 5 - 13 \Rightarrow - 8 = - 8$
here $L H S = R H S$
Hence verified.

Suggest Corrections

Similar questions

A = [\begin{matrix} - 2 \\ 4 \\ 5 \end{matrix}]

If A = {1, 2, 3}, B = {4} and C = {5}, then verify that :

(i) $A \times (B \cup C) = (A \times B) \cup (A \times C)$

(ii) $A \times (B \cap C) = (A \times B) \cap (A \times C)$

(iii) $A \times (B - C) = (A \times B) - (A \times C)$

If $a = - 13, b = 5 a n d c = - 11$ verify that $(a + b) + c = a + (b + c)$

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 3 5 & 0 & 2 1 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 3 & - 1 & 2 4 & 2 & 5 2 & 0 & 3 \end{matrix} ⎤ ⎥ ⎦

C = ⎡ ⎢ ⎣ \begin{matrix} 4 & 1 & 2 0 & 3 & 2 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦,

(A + B)

(B - C) .

A + (B - C) = (A + B) - C

Join BYJU'S Learning Program