If $a = - 13, b = 5 a n d c = - 11$ verify that $(a + b) + c = a + (b + c)$

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Solution

As $a = - 13, b = 5 a n d c = - 11$
To Verify, $(a + b) + c = a + (b + c)$
$\Rightarrow (- 13 + 5) + (- 11) = - 13 + [(5 + (- 11)] \Rightarrow - 8 - 11 = - 13 + (5 - 11) \Rightarrow - 19 = - 13 + (- 6) \Rightarrow - 19 = - 13 - 6 \Rightarrow - 19 = - 19$
Here, $L H S = R H S$
Hence verified.

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If A = {1, 2, 3}, B = {4} and C = {5}, then verify that :

(i) $A \times (B \cup C) = (A \times B) \cup (A \times C)$

(ii) $A \times (B \cap C) = (A \times B) \cap (A \times C)$

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If $a = - 13, b = 5 a n d c = - 11$ Verify that $a + b = b + a$

a = - 8, b = - 7

c = 6

(a + b) + c = a + (b + c)

A = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & - 3 5 & 0 & 2 1 & - 1 & 1 \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 3 & - 1 & 2 4 & 2 & 5 2 & 0 & 3 \end{matrix} ⎤ ⎥ ⎦

C = ⎡ ⎢ ⎣ \begin{matrix} 4 & 1 & 2 0 & 3 & 2 1 & - 2 & 3 \end{matrix} ⎤ ⎥ ⎦,

(A + B)

(B - C) .

A + (B - C) = (A + B) - C

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