Question

If $A={15}^o$, verify that $4\sin 2A.\cos 4A.\sin 6A=1$

Answer 1

$A={15}^{\circ }$

Therefore,

$4\sin 2A\cos 4A\sin 6A$

$=4\sin {30}^{\circ }\cos {60}^{\circ }\sin {90}^{\circ }$

$=4\times \frac{1}{2}\times \frac{1}{2}\times 1$

$=1$