If a 1 x - b 1 y - c 1-0- a 2 x - b 2 y - c 2-0 are two equations with no solutions- then a 1- a 2- b 1- b 2 - c 1- c 2A- FalseB- True

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Byju's Answer

Standard IX

Mathematics

Role of Coefficients and Constants

If a 1 x + b ...

Question

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with no solutions , then $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

True

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False

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Solution

The correct option is A
True

$a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with no solutions(inconsistent),then

$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

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Q. If

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and

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If a1x+b1y+c1=0, a2x+b2y+c2=0 are two equations with no solutions , then a1a2=b1b2≠c1c2

The correct option is A True a1x+b1y+c1=0, a2x+b2y+c2=0 are two equations with no solutions(inconsistent),then a1a2=b1b2≠c1c2

If $a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with no solutions , then $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

The correct option is A
True

$a_{1} x + b_{1} y + c_{1} = 0, a_{2} x + b_{2} y + c_{2} = 0$ are two equations with no solutions(inconsistent),then

$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$