If A - -2- -1- 0- 1- 2 f - A- Z- fx - x2 - 1- then the range of f is

The correct option is B {1, 2, 5} Given A = { 2, 1, 0, 1, 2} amp; f : A → Z; and f(x) = x^2 + 1 Thus range of f is ...

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Standard XII

Mathematics

Definition of Functions

If A = -2, ...

Question

If $A = {- 2, - 1, 0, 1, 2}$ & $f : A \to Z; f (x) = x^{2} + 1$ , then the range of $f$ is

{0, 1, 2, 5}

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{1, 2, 5}

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{- 5, - 2, 1, 3}

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{1, 2}

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Solution

The correct option is B ${1, 2, 5}$
Given $A = {- 2, - 1, 0, 1, 2}$ & $f : A$ $\to$ Z;
and $f (x) = x^{2} + 1$
Thus range of $f$ is $= {(- 2)^{2} + 1, (- 1)^{2} + 1, 0^{2} + 1, (1)^{2} + 1, (1)^{2} + 1, (2)^{2} + 1} = {1, 2, 5}$

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Similar questions

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If A={−2,−1,0,1,2} & f:A→Z;f(x)=x2+1, then the range of f is

The correct option is B {1,2,5}Given A={−2,−1,0,1,2} & f:A → Z; and f(x)=x2+1Thus range of f is ={(−2)2+1,(−1)2+1,02+1,(1)2+1,(1)2+1,(2)2+1}={1,2,5}

If $A = {- 2, - 1, 0, 1, 2}$ & $f : A \to Z; f (x) = x^{2} + 1$ , then the range of $f$ is

The correct option is B ${1, 2, 5}$
Given $A = {- 2, - 1, 0, 1, 2}$ & $f : A$ $\to$ Z;
and $f (x) = x^{2} + 1$
Thus range of $f$ is $= {(- 2)^{2} + 1, (- 1)^{2} + 1, 0^{2} + 1, (1)^{2} + 1, (1)^{2} + 1, (2)^{2} + 1} = {1, 2, 5}$