Question

If $A(2,1),B(0,5)$ are limiting points of a coaxial system then the radical axis of the conjugate coaxial system is

• A. $2x+y-5=0$
• B. $2x-y-3=0$
• C. $x-2y+5=0$
• D. $x+2y-7=0$

Answer 1

Answer: (A)

$2x+y-5=0$

Radical axis of conjugate coaxial system will pass through A and B.
Thus it's equation is given by,
$(y-5)=\frac{1-5}{2-0}(x-0)$

$=>y-5=-2x$

$=>2x+y-5=0$