Question

If A(2, -3), B(3,2), C(1,-2) and D(5, -4) are four points, then AB = CD.

• A. True
• B. False

Answer 1

The correct option is B

False

The distance between two points $(x_1,y_1)and(x_2,y_2)$ is given by
$\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2.}$

Given four points are: A(2, -3), B(3,2), C(1,-2) and D(5, -4)

$A{B}^2=(3-2{)}^2+(2-(-3){)}^2.$

$=1+25=26$

$C{D}^2=(5-1{)}^2+(-4-(-2){)}^2.$

$=16+4=20$

Since $A{B}^2\ne C{D}^2,AB\ne CD$

The given statement is false