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Question

If a2+4b2=12ab, then log(a + 2b) is

A
12[log a+log blog 2]
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B
loga2+logb2+log 2
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C
12[log a+log b+4 log 2]
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D
12[log alog b+4 log 2]
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Solution

The correct option is C 12[log a+log b+4 log 2]
a2+4b2=12aba2+4b2+4ab=16ab(a+2b)2=16ab
2log(a+2b)=log 16+log a+log b
log(a+2b)=12[log a+log b+4 log 2]

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