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B
a+b+c=−p
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C
ab+bc+ca=p
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D
ab+bc+ca=0
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Solution
The correct options are Ba+b+c=−p Dab+bc+ca=0 Let a2(a+p)=b2(b+p)=c2(c+p)=k. Then, a3+a2p−k=0,b3+b2p−k−0,c3+c2p−k=0. Hence, a,b,c are roots of equation x3+px2−k=0, where, a+b+c=−p ab+bc+ca=0