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Question

If a2(a+p)=b2(b+p)=c2(c+p), then

A
a+b+c=0
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B
a+b+c=p
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C
ab+bc+ca=p
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D
ab+bc+ca=0
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Solution

The correct options are
B a+b+c=p
D ab+bc+ca=0
Let a2(a+p)=b2(b+p)=c2(c+p)=k.
Then, a3+a2pk=0,b3+b2pk0,c3+c2pk=0.
Hence, a,b,c are roots of equation x3+px2k=0,
where,
a+b+c=p
ab+bc+ca=0

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