If $a^{2} - b^{2} > 0$ where $a > 0$ then

a > b

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b > a

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a < - b

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b > - a

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Solution

The correct options are
A $a > b$
B $b > - a$
$a^{2} - b^{2} > 0$
$\Rightarrow (a + b) (a - b) > 0$
$\Rightarrow a + b > 0$ and $a - b > 0$ or
$\Rightarrow a + b < 0$ and $a - b < 0$
$a > 0$ ...... $(g i v e n)$
So, $a > - b$ and $a > b$
Hence, option $A$ and $D$ both are correct answers.

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