If $a^{2} + b^{2} = 10$ and $a b = 3$ , then find $a + b$ .

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Solution

The correct option is A 4
Formula ${(a + b)}^{2} = a^{2} + b^{2} + 2 a b$
Given, $a^{2} + b^{2} = 10$ and $a b = 3$
So, ${(a + b)}^{2} = a^{2} + b^{2} + 2 a b = 10 + 2 \times 3 = 10 + 6 = 16$

$=> a + b = \sqrt{16} = 4$

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