If $a^{2} + b^{2} = 29$ and $a b = 10$ , then find $a - b$ .

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Solution

The correct option is B 3
Formula ${(a - b)}^{2} = a^{2} + b^{2} - 2 a b$
Given, $a^{2} + b^{2} = 29$ and $a b = 10$
So, ${(a - b)}^{2} = a^{2} + b^{2} - 2 a b = 29 - 2 \times 10 = 29 - 20 = 9$
$=> a - b = \sqrt{9} = 3$

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