If $a^{2} + b^{2} = 41$ and $a b = 4$ , then find $a - b$ .

\sqrt{35}

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\sqrt{33}

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Solution

The correct option is B $\sqrt{33}$
Formula ${(a - b)}^{2} = a^{2} + b^{2} - 2 a b$
Given, $a^{2} + b^{2} = 41$ and $a b = 4$
So, ${(a - b)}^{2} = a^{2} + b^{2} - 2 a b = 41 - 2 \times 4 = 41 - 8 = 33$

$=> a - b = \sqrt{33}$

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