If a2+b2,ab+bc and b2+c2 are in G.P., then a,b,c are in
A
A.P.
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B
G.P.
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C
H.P.
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D
None of these
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Solution
The correct option is B G.P. a2+b2,ab+bc,b2+c2 are in G.P. ⇒(ab+bc)2=(a2+b2)(b2+c2) ⇒a2b2+b2c2+2ab2c=a2b2+a2c2+b2c2+b4 ⇒b4+a2c2−2ab2c=0 ⇒(b2−ac)2=0 ⇒b2=ac ⇒a,b and c are in G.P.