If a2-b2-c2-2- and f x -1-a2x 1-b2 x 1-c2 x 1-a2 x 1-b2x 1-c2 x 1-a2 x 1-b2 x 1-c2xthen fx is a polynomial of degree

The correct option is C 2 f( x ) = 1+a^ 2 x amp; ( 1+b^ 2 ) x amp; ( 1+c^ 2 ) x ( 1+a^ 2 ) x amp; 1+b^ 2 x amp; ( 1+c^ 2 ) x ( 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of n Terms

If a2+b2+c2...

Question

If $a^{2} + b^{2} + c^{2} = - 2$ , and
$f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} x & (1 + b^{2}) x & (1 + c^{2}) x (1 + a^{2}) x & 1 + b^{2} x & (1 + c^{2}) x (1 + a^{2}) x & (1 + b^{2}) x & 1 + c^{2} x \end{matrix} ∣ ∣ ∣ ∣ ∣$
then $f (x)$ is a polynomial of degree

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

a^{2} + b^{2} + c^{2} = - 2

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} {1 + a}^{2} x & {(1 + b}^{2}) x & ({1 + c}^{2}) x ({1 + a}^{2}) x & {1 + b}^{2} x & ({1 + c}^{2}) x ({1 + a}^{2}) x & ({1 + b}^{2}) x & {1 + c}^{2} x \end{matrix} ∣ ∣ ∣ ∣ ∣

f (x)

a^{2} + b^{2} + c^{2} + 2 = 0

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} x & (1 + b^{2}) x & (1 + c^{2}) x (1 + a^{2}) x & 1 + b^{2} x & (1 + c^{2}) x (1 + a^{2}) x & (1 + b^{2}) x & 1 + c^{2} x \end{matrix} ∣ ∣ ∣ ∣ ∣

f (x)

If a² +b² + c² =-2 and

then f(x) is a polynomial of degree

a^{2} + b^{2} + c^{2} = - 2

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} x & (1 + b^{2}) x & (1 + c^{2}) x (1 + a^{2}) x & 1 + b^{2} x & (1 + c^{2}) x (1 + a^{2}) x & (1 + b^{2}) x & 1 + c^{2} x \end{matrix} ∣ ∣ ∣ ∣ ∣

a^{2} + b^{2} + c^{2} = - 2

A = ⎡ ⎢ ⎢ ⎣ \begin{matrix} 1 + a^{2} x & (1 + b^{2}) x & (1 + c^{2}) x (1 + a^{2}) x & 1 + b^{2} x & (1 + c^{2}) x (1 + a^{2}) x & (1 + b^{2}) x & 1 + c^{2} x \end{matrix} ⎤ ⎥ ⎥ ⎦

A

x =

Join BYJU'S Learning Program