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Question

If a2+b2+c2 = 2 and f(x) = ∣ ∣ ∣1+a2x(1+b2)x(1+c2)x(1+a2)x1+b2x(1+c2)x(1+a2)x(1+b2)x1+c2x∣ ∣ ∣ then f(x) is a polynomial of degree

A
3
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B
1
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C
2
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Solution

The correct option is C 2
Applying C1 C1+C2+C3
f(x) = ∣ ∣ ∣1(1+b2)x(1+c2)x11+b2x(1+c2)x1(1+b2)x1+c2x∣ ∣ ∣, ( a2+b2+c2+2=0)
[Applying R2 R2R1, R3 R3R1]=∣ ∣ ∣1(1+b2)x(1+c2)x01x0001x∣ ∣ ∣ = (1x)2.
Hence degree of f(x) = 2.

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