If $a^{2} + b^{2} + c^{2} = 20$ and $a + b + c = 0$ , find $a b + b c + c a$ .

Open in App

Solution

( a+ b + c) 2 = a2 + b2 + c2 + 2 ( ab + bc + ac)
ab + bc + ac = --20 / 2 = -10

Suggest Corrections

Similar questions

a + b + c = 0

\frac{a^{2}}{b c} + \frac{b^{2}}{c a} + \frac{c^{2}}{a b}

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

If $a + b + c = 7$ and $a b + b c + c a = 20$ find the value of $a^{2} + b^{2} + c^{2}$

a + b + c = 0

\frac{a^{2}}{b c} + \frac{b^{2}}{c a} + \frac{c^{2}}{a b} =

a + b + c = 0

\frac{(b + c)^{2}}{b c} + \frac{(c + a)^{2}}{c a} + \frac{(a + b)^{2}}{a b}

Join BYJU'S Learning Program