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if a =-2,b=-3 ,c=4 find 5 a^2b^3c+3a^3b^2c^2-(-2)^2(-3)^2*4*4

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If your question is exactly as follows ,solution is given below
if a =-2,b=-3 ,c=4 find 5 a^2b^3c+3a^3b^2c^2-(-2)^2(-3)^2*4*4
a =-2,b=-3 ,c=4
5a^2b^3c=5*-2^-6^12=(-10)^6*12=(-10)^72
3a^3b^2c^2=-6^-6^8^2=(-6)^-6*8*2=(-6)^-96
(-2)^2=4
(-3)^2*4*4=(-3)^32
(-2)^2(-3)^2*4*4=4*(-3)^32
Therefore 5 a^2b^3c+3a^3b^2c^2-(-2)^2(-3)^2*4*4=(-10)^72+(-6)^-96-4*(-3)^32
=10^72+5.04*10^74+7.41*10^15
=5.041*10^75

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