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Question

If a2(b+c),b2(c+a),c2(a+b) are in AP, then a,b,c are in

A
AP
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B
GP
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C
HP
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D
None of these
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Solution

The correct option is A AP
Given: a2(b+c),b2(c+a),c2(a+b) are in AP
2b2(c+a)=a2(b+c)+c2(a+b)
2b2c+2ab2=a2b+a2c+ac2+bc2
bc(2bc)+ab(2ba)=ac(a+c)
We know: 2b=a+c
bc(a)+ab(c)=ac(a+c)
2abc=ac(a+c)
2b=a+c
a,b,c are in A.P.

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