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B
2
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C
4
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D
6
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Solution
The correct option is B 2 Given that A+A=B⇒2A=BA+A=B⇒2A=B and A2=BA2=B Therefore, 2A=A22A=A2 or A2−2A=0A2−2A=0 or A(A−2)=0A(A−2)=0 Hence, A=0,2A=0,2 since, A=0A=0 is not an option, therefore, A=2A=2 option (2).