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Question

If a2=logx,b3=logy and 3a2โˆ’2b3=6logz, then express y in terms of x and z

A
y=x32÷z5
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B
y=x23÷z3
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C
y=x32÷z3
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D
y=x32÷z2
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Solution

The correct option is D y=x32÷z3
a2=logx,b3=logy
3a22b3=6logz
x=10a2,y=10b3,z=1016(3a22b3) ...(1)
z=10a2/210b3/3 ...(2)
From 1 and 2 we get
z=x12y13 and y=x32z3

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