If A=2tanB+cotB, then 2tan(A−B)= ?
2tan(A-B)=2{tanA-tanB/1+tanAtanB}
Given:tanA=2tanB+cotB
2tanA=tanB+tanB+1/tanBtanA-tanB={(tan^2B+1)/(tanB)
From 2tanAtanB=2tan^2B+1
Substitute 3 and 4 in 1
You get2tan(A-B)=2
{tan^2B+1)/(tanB)/2tan^2B+2}2tan(A-B)
={(tan^2B+1)/(tanB)/tan^2B+1}2tan(A-B)
=(1/tanB)2tan(A-B)=cotB