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Question

If A=235-2 be such that A-1=k A, then find the value of k.

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Solution

A=2 35 -2A =2 35 -2 =-14-15=-19 The value is non-zero, so A-1 exists.By definition, we have A-1 A=I [I is the identity matrix]kA.A =I [Substituting A-1=kA]k2 35 -22 35 -2=1 00 1k4+15 6-610-10 15+4=1 00 1k19 00 19=1 00 1k=119

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