Question

If $A(-2,4),B(0,0)$ and $C(4,2)$ are the vertices of a $△ABC$, then find the length of median through the vertex $A$.

• A. $2$
• B. $4$
• C. $3$
• D. $5$

Answer 1

The correct option is D $5$

$D=$slid $ht$ of $BC$

$D\cong (\frac{0+4}{2},\frac{0+2}{2})$

$=(2,1)$

$\therefore$ Length of median $=$ Light of $AD$

$=\sqrt{(-2-2{)}^2+(4-1{)}^2}$

$=\sqrt{4^2+3^2}$

$=5$