Question

If $a=29,b=24$ and $c=27$ find the value of $a^3+b^3+c^3-3abc$.

• A. $1620$
• B. $1640$
• C. $1520$
• D. $1580$

Answer 1

The correct option is C $1520$

Given $a=29,b=24,c=27$

We know that $a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)$

Now put the value of $a,b,c$ in above formula,we get

$a^3+b^3+c^3-3abc=(29+24+27)({29}^2+{24}^2+{27}^2-29\times 24-24\times 27-27\times 29)$

On solving above equation, we will get

$a^3+b^3+c^3-3abc=1520$