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Question

If A (2a,4a) and B (2a,6a) are two vertices of a equilateral triangle ABC then the vertex C is given by

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Solution

AB=(2a2a)2+(6a4a)2=2a
then BC=2a=(x2a)2+(y6a)2
also
AC=2a=(x2a)2+(y4a)2
on solving,
x=(3+2)a y=5a
c((3+2)a,5a)


1374865_1161569_ans_7ff7189b0fde4886b3b89f652ef30696.png

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