CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Types of Brackets

If a-2 b-2 b-...

Question

If $(a - 2 b) - (2 b - a)$ = $x$ , then $x$ is

A

$2 (a - b)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

$2 (a - 2 b)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

$a - 2 b$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

$2 (2 a - b)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$2 (a - 2 b)$

$(a - 2 b) - (2 b - a)$ = $a - 2 b - 2 b + a$ = $2 a - 4 b$ = $2 (a - 2 b)$

Suggest Corrections

thumbs-up

0

Similar questions

x = \frac{\sqrt{a + 2 b} + \sqrt{a - 2 b}}{\sqrt{a + 2 b} - \sqrt{a - 2 b}}

then prove that

b x^{2} - a x + b = 0

x = \frac{4 a b}{a + b}

\frac{x + 2 a}{x - 2 a} + \frac{x + 2 b}{x - 2 b}

x = \frac{\sqrt{a + 2 b} + \sqrt{a - 2 b}}{\sqrt{a + 2 b} - \sqrt{a - 2 b}}

, then show that

b x^{2} - a x + b = 0

x = \frac{4 a b}{a + b}

, then prove that

\frac{x + 2 a}{x - 2 a} + \frac{x + 2 b}{x - 2 b} = 2

t a n x = \frac{2 b}{a - c} (a \neq c), y = a c o s^{2} x + 2 b s i n x c o s x + c s i n^{2} x a n d z = a s i n^{2} x - 2 b s i n x c o s x + c o s^{2} x,

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Types of Brackets

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon