CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
80
You visited us 80 times! Enjoying our articles? Unlock Full Access!
Question

If a+2b+3c=0,prove that a3+8b3+27c3=18abc

Open in App
Solution

A+2b+3c=0 then

a+2b=-3c

(a+2b)^3=(-3c)^3 (By cubing)

a^3+(2b)^3+3(a)(2b)(a+2b) = -27c^3

a^3+8b^3+6ab (-3c) = -27c^3 [a+2b=-3c]

a^3+8b^3-18abc = -27c^3

a^3+8b^3+27c^3 = 18abc

Hence proved...

flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Polynomials in One Variable
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon