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Question

If a+2b+c=4 and a,b,cR, then the maximum value of (ab+bc+ca) is

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Solution

Given a+2b+c=4
a=42bc
Let ab+bc+ca=y
a(b+c)+bc=y
(42bc)(b+c)+bc=y
2b2+2(c2)b4c+c2+y=0

Since, bR
So, D0
4(c2)24×2(4c+c2+y)0
c24c+2y40

Since, cR
So, D0
164(2y4)0
y4

max(ab+bc+ca)=4

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