Question

If A(−3, 5), B(−2, −7), C(1, −8) and D(6, 3) are the vertices of a quadrilateral ABCD, find its area.                          [CBSE 2014]

Solution

It is given that A(−3, 5), B(−2, −7), C(1, −8) and D(6, 3) are the vertices of a quadrilateral ABCD. Area of the quadrilateral ABCD = Area of ∆ABC + Area of ∆ACD ∴ Area of the quadrilateral ABCD = $\frac{35}{2}+\frac{109}{2}=\frac{144}{2}=72$ square units Hence, the area of the given quadrilateral is 72 square units.MathematicsRD Sharma (2016)Standard X

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