If $a = 3$ and $b = - 2$ , find the values of: $a^{a} + b^{b}$

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Solution

Given that,
$a = 3, b = - 2$

$a^{a} + b^{b} = 3^{3} + (- 2)^{(- 2)}$

$= 27 + \frac{1}{(- 2)^{2}}$

$= 27 + \frac{1}{4}$

$= \frac{109}{4}$

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