Question

If a = 3, b = 0 and c = -2, then the value of (ab+2bc +3ca+4abc) is

• A. -18
• B. 0.0
• C. -24
• D. -12

Answer 1

The correct option is A -18

$\text{Given,}a=3,b=0\text{and}c=-2.$
$\text{Then,}ab+2bc+3ca+4abc=(3\times 0)+(2\times 0\times (-2\left)\right)+(3\times (-2)\times 3)+(4\times (3)\times 0\times (-2\left)\right)=0+0+(-18)+0=-18$