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Division of a Polynomial by a Monomial

If a=3,b=0,c=...

Question

If $a = 3, b = 0, c = 2, a n d d = 1,$
Find the value of
$3 a + 2 b - 6 c + 4 d$

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Solution

Find the value of $3 a + 2 b - 6 c + 4 d$

Substituting $a = 3, b = 0, c = 2, a n d d = 1$ in $3 a + 2 b - 6 c + 4 d$
we get:

$3 a + 2 b - 6 c + 4 d = 3 (3) + 2 (0) - 6 (2) + 4 (1)$
$= 9 + 0 - 12 + 4$
$= 13 - 12$
$= 1$

Therefore,the value of $3 a + 2 b - 6 c + 4 d$ is $1.$

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Division of a Polynomial by a Monomial

Standard VIII Mathematics

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