If $a = 3, b = 0, c = 2, and d = 1$ , Find the value of $3 a + 2 b - 6 c + 4 d$ .

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Solution

Step: Finding the value of $3 a + 2 b - 6 c + 4 d$ .
Substituting, $a = 3, b = 0, c = 2, and d = 1 in 3 a + 2 b - 6 c + 4 d$ .
We get,
$3 a + 2 b - 6 c + 4 d = 3 (3) + 2 (0) - 6 (2) + 4 (1)$
$= 9 + 0 - 12 + 4$
$= 13 - 12$
$= 1$
Therefore, the value of $3 a + 2 b - 6 c + 4 d is 1$ .

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