If $a = 3, b = 0, c = 2, and d = 1$ , Find the value of $a b c - b c d + c d a$ .

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Solution

Step: Finding the value of $a b c - b c d + c d a$ .
Substituting, $a = 3, b = 0, c = 2, and d = 1 in a b c - b c d + c d a$
We get,
$a b c - b c d + c d a = (3 \times 0 \times 2) - (0 \times 2 \times 1) + (2 \times 1 \times 3)$
$= 0 - 0 + 6$
$= 6$
Therefore, the value of $a b c - b c d + c d a is 6$ .

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