Question

If \(a = 3, b = 0, c = 2, ~\text{and}~ d = 1\), Find the value of \(a^2 + 2b^2 - 3c^2\).

Answer 1

Step: Finding the value of \(a^2 + 2b^2 - 3c^2\).
Substituting, \(a = 3, b = 0, c = 2, ~\text{and}~ d = 1~\text{in}~a^2 + 2b^2 - 3c^2\)
We get,
\(a^2 + 2b^2 - 3c^2 = (3)^2 - 2(0)^2 - 3(2)^2 \)
\(= 9 - 2(0) + 3(4)\)
\(= 9 - 12 \)
\( = -3 \)
Therefore, the value of \(a^2 + 2b^2 - 3c^2~\text{is}~-3\).