Question

If $a=3,b=2$ and $c=-1$, then the value of $\left(\frac{a}{b}+\frac{b}{c}-\frac{c}{a}\right)$ is equal to

• A. $\frac{2}{3}$
• B. $\frac{1}{6}$
• C. $\frac{-1}{6}$
• D. $-1\frac{1}{6}$

Answer 1

The correct option is C $\frac{-1}{6}$

$\frac{a}{b}+\frac{b}{c}-\frac{c}{a}=\frac{3}{2}+\frac{2}{-1}-\frac{-1}{3}$
$=\frac{3}{2}-\frac{2}{1}+\frac{1}{3}$
$=\frac{9-12+2}{6}$
$=\frac{-1}{6}$